In how many ways an examiner can assign 30marks to 8 questions, giving not less than 2 marks to any question
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Answer:
Give 2 marks to all 8 questions first... You given total 16 marks...
Now only 14 marks left...
Now you have to give 14 marks to 8 questions without any condition on the left marks....
So it's equivalent to fill 14 balls in 8 bags...
Applying the same concept...
It is.... {14+(8-1)}!/14!(8-1)!
21!/14!7!
=116280...
I may be wrong....
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