In how many ways can 2310 be expressed as product of three factors?? 1) 41 2) 56 3) 23 4) 46
Answers
Answered by
14
We have to calculate the prime factors of 2310.
Prime factorization of 2310 = 2 * 3 * 5 * 7 * 11.
We know that when a number is expressed as n distinct primes, then the product of three numbers can be expressed as:
= > [3^(n + 1) + 1]/2
= > [3^(3 + 1) + 1]/2
= > [3^4 + 1]/2
= > 82/2
= > 41.
Therefore, the total number of ways = 41.
The answer is option (1) - 41.
Hope this helps!
Answered by
0
Answer:if you feel help full than please like, thank you..
Step-by-step explanation:
Prime factors of 2310=2×5×7×3×11.
The required number of factors in2310 = the number of selections of one or more of the 4 prime factors = 2^5-1 = 31.
THEREFORE ANSWER IS 31.
........THANK YOU........
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