In how many ways can 6 letters a, b, c, d, e and f be arranged in a row such that d is always somewhere between a and b?
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As d is always between a and b, positon of d is fixed that is it always come before b.
there are 5 ways for A to take positon in a row as it can't take position at last
there are 4 ways for B and D to take position in a row as there position is fixed
there are 4 ways for C to take position in a row and 3 way for E and 2 for F.
No of ways of arrangement of all the letters=
5*4*4*3*2/2 = 240
Answer = 240
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