Math, asked by Shantanum8399, 1 year ago

In how many ways can 60060 be written as a product of two factor

Answers

Answered by Ramanan2018
0

Answer:

Step-by-step explanation:

Idk

Answered by rahul123437
0

Factors

Number given as 60060.

First , we will write this number as the product of prime factors.

60060=2\times2\times3\times5\times7\times11\times13

60060=2^2\times3^1\times5^1\times7^1\times11^1\times13^1

If the prime factorization of a number (composite)  N={a^m}\times b^n\times c^p....and \ so \ on

then the number of its factors will be (m+1)(n+1)(p+1)..

  • If the number of factors comes as even, number of ways number can be written as product of two factors as, \frac{number\ of \ factors}{2}
  • If it is odd then,

       number of ways will be,

       \frac{number\ of \ factors\ +1}{2}

In this case,

number of ways will be ,(2+1)(1+1)(1+1)(1+1)(1+1)(1+1)=3\times2\times2\times2\times2\times2=96

Hence, the required number of ways will be \frac{96}{2} =48.

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