Question

In how many ways can 7 examination papers be arranged so that the papers 6 and 7 are never together?

Answer 1

Answer:

here is the answer below

Step-by-step explanation:

This can be solved in 3 steps for better understanding.

Step 1:

Total number of ways of arranging 9 papers at 9 places (irrespective of any condition) = 9!

Step 2:

Now, the number of ways of arranging 9 paper at places such that the worst paper and the best paper are always together = 8! * 2!

Step 3:

Total no of ways of arranging 9 papers at 9 places such that the beat and the worst doesn’t come together = 9! - 8!*2!

= 8! (9–2) = 8! X 7 ways