Question

In how many ways can 7 plus(+) signs and 5 minus (-) signs be arranged in a row so that no two minus signs are together?

Answer 1

Answer:

56

Step-by-step explanation:

Given In how many ways can 7 plus(+) signs and 5 minus (-) signs be arranged in a row so that no two minus signs are together?

Given that no 2 minus signs are together. We have 7 + and 5 – signs.

Number of arrangements = 1

By taking + signs there are total 8 gaps.

- + - + - + - + - + - + - + -

We need to choose 5 gaps out of 8 gaps, so number of ways will be

8 C 5 = 8! / 5! (8 – 5)!

       = 56

So this can be done in 56 ways.

Answer 2

Step-by-step explanation:

Hi

8C5

8!/5!(8-5)!

=>8!/5!3!

56