Math, asked by karina469, 1 year ago

In how many ways can a party of 6 men and 6 women be seated at a round table , so that no women are adjacent​

Answers

Answered by kirudhivi
0

I think answer is 4,4,4

Answered by nessintin12
2

Step-by-step explanation:

the women have to be seated leaving one chair gap so that they are no adjacent.

so the men can be seated in 6! ways and the women can be replaced in 6! ways ...

so no of possible events

6!+6!

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