Question

in how many ways can bunette letters of the word can be arranged​

Answer 1

Answer:

Given:

The word ARRANGE. It has a total of 7 words out of which there are two A’s and two R’s and the rest three words are different.

Now, when we have n objects such that p items are of one type and q are of another type and the rest r are different objects, so n=p+q+r . Then, we can arrange them in n!(p!)(q!) ways.

Now, in our question, we have word ARRANGE where total 7 words are there out of which 2 are A’s and 2 are R’s and rest 3 are different then, the total number of ways in which letters of the given word can be arranged will be 7!(2!)(2!)=1260 .

(a) The two R’s are never together:

Now, for this case we will club the two R’s together and treat it as one single letter then we will have a total 6 words out of which