In how many ways can the letterof the word" parallel" be arranged so that all l's do not come together
Answers
Answered by
0
Answer:
Here is ur answer,
Step-by-step explanation:
The given word 'PARALLEL' has 8 letters, out of which there are 2 A's, 3 L's, 1 P, 1 R and 1 E.
Number of their arrangements =8!/(2!)×(3!)=3360.
Let us assume LLL as 1 letter.
Then, LLL + PARAE has 6 letters, out of which there are 2 A's and the rest are all distinct.
Number of their arrangements =6!/2!=360.
Number of arrangements in which 3 L's are not together =(3360−360)=3000.
Hope It will help u
Mark Me As Brainlist
Similar questions