Question

In how many ways eleven players can be selected from batch of fifteen players

Answer 1

Total no. of players-15

Make selection of 11 players

So, the no. of ways will be-

$15c11 \\ \frac{15!}{4! \times 11!} \\ = \frac{15 \times 14 \times 13 \times 12 \times 11!}{4! \times 11!} \\ = \frac{15 \times 14 \times 13 \times 12}{4 \times 3 \times 2} \\ = 105 \times 13 \\ = 1365$