Math, asked by ibbitahir9222, 1 year ago

In how many ways is it possible to choose a white square and black square on a chessboard so that the squares must not lie in the same row or same column?

Answers

Answered by VaibhavSR
0

Answer: 768

Step-by-step explanation:

  • A chessboard contains 32 white squares, so you have 32 possible choices for the white square.
  • Now in the same column or row of this square lie black square which you can't choose
  • No. of possible black squares that could be chosen=32-8

                                                                                                   =24

  • Total number of choices left= 32×24

                                                         = 768

  • Hence,there are 768 ways to choose the desired white and black square not lying in the same row or column.

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