Question

Initially a car a is 21 m ahead of car

b. Both start moving at t=0 in same dirrection along straight line. If a is moving wth constant velocity 20m/s and b starts from rest with an acceleration 2m/s towards a

Answer 1

Answer:

Explanation:The relative speed of B wrt A will be VBA​=VB​−VA​=20−0=−20m/s

their relative acceleration will be aBA​=aB​−aA​=2−0=2m/s2

the distance traveled will be given by   s=ut+21​at2=−20t+21​2×(t)2=21meter

on solving it we get t=21sec

Just employ the Shridharacharya Formula t=2a−b±b2−4ac

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Where t is root of at2+bt+c=0