Question

In how many ways of the distinct permutations of the letter in mississippi do the four i's not come together?

Answer 1

First find the
total no of permutation possible=(11!/4!4!2!)
=34650

As 's' and 'i' are repeated 4 times and 'p' is repeated 2 times, that is why 11! is divided by 4!x4!x2!
Now assume the 4 i's together as one word
The no. of letters left is 8.
1-m 4-s 2-p and 1-containing 4 i's.

The permutation for 4 i's together will be= 8!/(4!2!)
=840
We want no. of permutation in which 4i's are not together
P= Total permutation - permutation of 4 i's together

After solving
P=33810