In how many ways the 26 letters of the English alphabet can permuted so that none of the word SUN , TEA , BOY or GIRL occurs?
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Answer:
Total number of permutations possible with 26 alphabets where SUN, TEA, BOY and GIRL occurs always, N(ABCD) = (26 - 3 - 3 - 3 - 4 + 4)! = 17! We can apply the principle of Inclusion and Exclusion to calculate the number of possible pemutations where none of the given pattern occur
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Explanation:
Explanation: Ways the 26 alphabets can be permuted so that SUN , TEA , BOY or GIRL occurs = 26! - [3(24
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