In how many ways the letters of the word commerce be arranged in which vowels are never together?
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The 5 consonants c,m,m,r,c can be arranged in 5!/2! ways.there are six places for three vowels o,e,e which can be arranged 6P3/2! ways.
So the number of arrangements
= (5!/2!)×(6P3/2!)
=60×60=3600
So the number of arrangements
= (5!/2!)×(6P3/2!)
=60×60=3600
Anonymous:
post kia h
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