In how many years will ₹4000amount to ₹463.50at 5%pa compounded anually
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Answer:
how can the amount decrease in some time
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1
Answer:
given..
R = principal amount =4000
c = compounded amount = 4630.5
n= no.of years = ?
i = rate of interest per annum = 5%
we know that c = p((1+i)^n
4530.5 = 4000((1+5%)^n
4530.5= 4000((1+0.05)^n
4530.5 = 4000((1.05)^n
4530.5/4000 = (1.05)^n
1.132625 = (1.05)^n
(1.05)^3 = (1.05)^n
powers are equal ..equate the powers....
n = 3.. so no.of uyears are 3
Step-by-step explanation:
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