Question

In how many years will ₹4000amount to ₹463.50at 5%pa compounded anually ​

Answer 1

Answer:

how can the amount decrease in some time

Answer 2

Answer:

given..

R = principal amount =4000

c = compounded amount = 4630.5

n= no.of years = ?

i = rate of interest per annum = 5%

we know that c = p((1+i)^n

4530.5 = 4000((1+5%)^n

4530.5=  4000((1+0.05)^n

4530.5 =  4000((1.05)^n

4530.5/4000 =  (1.05)^n

1.132625 =   (1.05)^n

(1.05)^3 = (1.05)^n

powers are equal ..equate the powers....

n = 3.. so no.of uyears are 3

Step-by-step explanation: