Math, asked by vars5h1ikatya, 1 year ago

in how many years will a sum of money double itself al 18.75% per annum simple interest. Plsssanswer fast

Answers

Answered by Lawliet
84
Let The Principal be x
R = 18.75%
T = y
A = 2x --------as the money doubles itself
A = P + I
2x = x + x*18.75*y/100 -----------[I = PRT/100] 
2x = x + 18.75xy/100
2x - x = 18.75xy/100
x = 18.75xy/100
100x = 18.75xy
100 = 18.75y ----------------[Dividing x on Both The Sides]
100/18.75 = y
y = 5.3333 Years
y = 5 1/3 Years
y = 5 Years 4 Months

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Answered by nalinsingh
25

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