In how many years will a sum of Rs 1000 invested at the rate of 8% p.a. simple interest
amount to
Rs 1200?
Answers
Answered by
1
SI = PTR/100 = 1000 x 8 x T/100
SIn= 1200 - 1000 = 200
200 = 1000x 8 x T/100
T = 10/4 = 2.5 years
Answered by
5
Step-by-step explanation:
We have :
A = 1200 ruppess ,P = 1000, R = 8%
:-) S.I = A - P = (1200 - 1000) = 200
Now, T = 100×S.I /P×R = [100×200/1000×8]years
= [25/10] =2.5 years.
Answer) 2.5 Years
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