Question

in how much time will the interest on rupees 800 at 12.5% per annum be rupees 125

Answer 1

S.I = (P × R × T)/100

R = (S.I × 100)/(P × T) 

P = (S.I × 100)/(R × T)

T = (S.I × 100)/(P × R)

If the denotes the amount, then A = P + S.I

hope this will help u.. if so then mark it as the brainliest answer........

Answer 2

Step-by-step explanation:

$\sf \leadsto T = \frac {(S.I × 100)}{(P × R)} \\ \sf \leadsto T = \frac{125\times 1 \cancel{00}}{8 \cancel{00} \times 12.5} \\ \sf \leadsto T = \frac{ \cancel{125} \times 10}{8 \times \cancel{125}} \\ \sf \leadsto T = \cancel{\frac{10}{8} } \\ \sf \leadsto T = \frac{5}{4} years \: ans. \\ \sf \: or \: 1year \: 3months$