In how much time would the simple interest on a certain sumbbe 0.125 timed the principal at 10%per annum
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We know that SI = P * T * R/100
0.125p = p * t * r/100
125/1000 = t/10
t = 1.25 years (or) 1 year or 3 months
0.125p = p * t * r/100
125/1000 = t/10
t = 1.25 years (or) 1 year or 3 months
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