Math, asked by sharmarushii55, 6 months ago

In Hyderabad, legal water connections form 80% of the total connections. If 90% of the houses in the city
have water connections, what percentage of the houses in the city have illegal water connections?​

Answers

Answered by Chandramathy
1

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Answered by RvChaudharY50
0

Given :- In Hyderabad, legal water connections form 80% of the total connections. If 90% of the houses in the city have water connections, what percentage of the houses in the city have illegal water connections ?

Solution :-

Let us assume that, Total houses in hyderabad are 100 .

given that,

→ Legal water connections = 80% of the total connections.

So,

→ Total number of Legal water connections = 80% of 100 = (80 * 100/100) = 80 connections .

now, we have given that,

→ Houses in the city have water connections = 90% .

So,

Total number of Houses in the city have water connections = 90% of 100 = (90 * 100) / 100 = 90 houses.

Therefore, we can conclude that, in total number of houses which have water connection, out of them 80 are legal connections.

Than,

→ Total number of houses that have illegal connections = 90 - 80 = 10 houses.

Hence,

Required % = 10 * 100 / 100 = 10% (Ans.)

10% of the houses in the city have illegal water connections.

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