Question

In hydrogen atom, an electron is revolving in the orbit of radius 0.53\,{AA}
with 6.6\times {{10}^{15}}
rotations/second. Magnetic field produced at the centre of the orbit is [MP PET 2003]
A) 0.125\,wb/{{m}^{2}} B) 1.25\,wb/{{m}^{2}} C) 12.5\,wb/{{m}^{2}} D) 125\,wb/{{m}^{2}}

Answer 1

Answer:

12.5 Wb/m^2

Explanation:

Data:

radius = r = 0.53 * 10^-10 m

The electron revolving with = 6.6 * 10^-15 radiation/s

Required:

magnetic field = B = ?

Calculation:

we know that

      B = k 2 π (Qv)/r

where  k is constant and its value is "10^-7"

Putting values we get

       B = (10^-7) . 2 (3.14)*(1.6*10^-19)*(1.6*10^15) / (0.53*10^-10)

⇒    B=12.5 Wb/(m^2)

So The answer is "12.5Wb/(m^2) "