Question

In hydrogen atom, an electron jumps from 3rd orbit to the 2nd orbit. Calculate the wavelength of the radiation emitted

Answer 1

Answer:

6.56×10⁻⁷m=656 nm

Explanation:

Using Rydberg's formula

1/λ=R(1/n₁²-1/n₂²)

⇒λ=1/(R)(1/4-1/9)=36/5×1/10973700≈6.56×10⁻⁷m=656nm

Answer 2

Answer:

Explanation:6.56×10⁻⁷m=656 nm

Explanation:

Using Rydberg's formula

1/λ=R(1/n₁²-1/n₂²)

⇒λ=1/(R)(1/4-1/9)=36/5×1/10973700≈6.56×10⁻⁷m=656nm