In hydrogen atom, an electron jumps from 3rd orbit to the 2nd orbit. Calculate the wavelength of the radiation emitted
Answers
Answered by
14
Answer:
6.56×10⁻⁷m=656 nm
Explanation:
Using Rydberg's formula
1/λ=R(1/n₁²-1/n₂²)
⇒λ=1/(R)(1/4-1/9)=36/5×1/10973700≈6.56×10⁻⁷m=656nm
Answered by
0
Answer:
Explanation:6.56×10⁻⁷m=656 nm
Explanation:
Using Rydberg's formula
1/λ=R(1/n₁²-1/n₂²)
⇒λ=1/(R)(1/4-1/9)=36/5×1/10973700≈6.56×10⁻⁷m=656nm
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