Question

In hydrogen atom second excited energy is

Answer 1

HYDROGEN ATOM:-

Atomic Number = 1

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2nd Excited state means the Third Orbit.

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To get the energy of any stationary state in an electron we have the Formula:-

$\boxed{\red{\bold{\sf{\Large{-13.6\dfrac{Z^2}{n^2}eV}}}}}$

Where:-

Z is the atomic Number and n is the Energy Level of the Atom or the number of the shell one is talking about.

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Applying the Formula For Z=1 and n=3 we have :-

$E_3=-13.6\dfrac{1^2}{3^2}\\ \\ \\E_3=\dfrac{-13.6}{9}\\ \\ \\E_3=(-1.5)eV$

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For Hydrogen Atom Energy of :-

Ground state = -13.6eV

First Excited State = -3.4eV

Second Excited State = -1.5eV

Third Excited State= -0.85eV

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Answer 2

$\Large{\mathfrak{\underline{\underline{Answer :-}}}}$

The second energy level is $-3.4 eV.$

Thus it would take $E_2$ − $E_1$ = $-3.4 eV$ − $-13.6 eV = 10.2 eV$ to excite the electron from the ground state to the first excited state.

If a photon has more energy than the binding energy of the electron then the photon will free the electron from the atom – ionizing it.

The ground state is the most bound state and therefore takes the most energy to ionize.