In hydrogen atom the electrical force of attraction between the electron and protons is 8.1×10‐⁸N .calculate the distance between the electron and the proton .Given charge on electron =1.6×10‐¹⁹C
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Answer:From Coulomb's inverse square law: F= 4πε
0
1
r
2
q
1
q
2
The magnitude of charge on electron and proton is the same =1.6×10
−19
C
Therefore, electrostatic force is given by
F=
(0.05×10
−9
)
2
9×10
9
×1.6×10
−19
×1.6×10
−19
=
(5×10
−11
)
2
9×1.6×1.6×10
−29
=
25×10
−22
9×1.6×1.6×10
−29
=0.9216×10
−29
×10
+22
=0.9216×10
−7
N
=9.216×10
−8
N
Explanation:
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