Three numbers are added together .the second number is 6 more that the first number and the third number is 15 less than the first number.the sum is 93
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Answered by
1
Let the first number = x
Second number = 6+x
Third number = x-15
Now, according to the question:-
x+6+x+x-15 = 93
3x-9 = 93
3x = 93+9
x = 102/3
x = 34
Here is your answer and hope it will help you.
Answered by
0
Answer:
We don’t know what they are, but we know there are three numbers and we know their sum. Let’s call them x, y, and z.
X+Y+Z= 93
The second piece says that whatever the second number, y, is, it is 6 times the first. So we know that
y = 6×X
Equation=X+6×X+Z= 93
The next piece of information is that the third number, z, is 15 less than the First . We know the second is now X , so we can say
z = X-7
Equation
X+6×X+X-7= 93
8X = 93-7
8X= 86
X= 86÷8
X=10.75
∴ First no.= 10.75
Second no.= 6×10.75
64.5
Third no.= 10.75-15
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