Math, asked by rachaelopoku3, 8 months ago

Three numbers are added together .the second number is 6 more that the first number and the third number is 15 less than the first number.the sum is 93

Answers

Answered by sunny2005rahul
1

Let the first number = x

Second number = 6+x

Third number = x-15

Now, according to the question:-

x+6+x+x-15 = 93

3x-9 = 93

3x = 93+9

x = 102/3

x = 34

Here is your answer and hope it will help you.

Answered by yadp006
0

Answer:

We don’t know what they are, but we know there are three numbers and we know their sum. Let’s call them x, y, and z.

X+Y+Z= 93

The second piece says that whatever the second number, y, is, it is 6 times the first. So we know that

y = 6×X

Equation=X+6×X+Z= 93

The next piece of information is that the third number, z, is 15 less than the First . We know the second is now X , so we can say

z = X-7

Equation

X+6×X+X-7= 93

8X = 93-7

8X= 86

X= 86÷8

X=10.75

∴ First no.= 10.75

   Second no.= 6×10.75

                          64.5

    Third no.= 10.75-15

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