Question

in hydrogen atom the electron is moving round the nucleus with velocity 2.8×10^6 m/s in an orbit of radius 0.528 Å. the acceleration of the electron is? ​

Answer 1

Answer:

Explanation:

We have

Velocity= 2.18*10^6 m/s

radius= 5.28*10^-11 m

Acc=?

Now we must know that this thing moves in orbit.. so it's circumference of orbit that counts as distance…

Distance= Circumference= 2πr

D= 3.31752*10^-10 m………… (just do direct calculation u will get it)

Velocity, V= D/T

so by that

T= D/V = 1.5218*10^-16 sec

Also we know that…

Acc= V/T

By considering the initial value that is,

Acc= 4.12878787*10^21 m/s/s ……..(or m/s2)

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Answer 2

answer is in the given attachment below