Physics, asked by anantkumar7210pael07, 9 months ago

In hydrogen atom the electron revolves around the
proton at a speed of 2.18 x 10^(6) m/s in a circle of
radius 5.28 x 10^(-11)m. Calculate the acceleration of
the electron and compare it with the acceleration due
to gravity.

Answers

Answered by RADJKRISHNA
10

hi friend,

here is your answer

Answer:

9 ×10^22 m/s ^2

Explanation:

a = v^2/r

= (2.18×10^6)^2/5.28×10^-11

= 0.9×10^23

= 9×10^22 m/s ^2

hope it helps

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Answered by BatoolAmina
0

Answer:

9×10²² ms–²

Explanation:

ac = v²/r

=(2.18×10⁶)²/(5.29×10–¹¹)

= 0.9×10²³

= 9×10²²

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