In hydrogen atom the electron revolves around the
proton at a speed of 2.18 x 10^(6) m/s in a circle of
radius 5.28 x 10^(-11)m. Calculate the acceleration of
the electron and compare it with the acceleration due
to gravity.
Answers
Answered by
10
hi friend,
here is your answer
Answer:
9 ×10^22 m/s ^2
Explanation:
a = v^2/r
= (2.18×10^6)^2/5.28×10^-11
= 0.9×10^23
= 9×10^22 m/s ^2
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Answered by
0
Answer:
9×10²² ms–²
Explanation:
ac = v²/r
=(2.18×10⁶)²/(5.29×10–¹¹)
= 0.9×10²³
= 9×10²²
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