Question

in in given figure, AD is bisector of angle BAC and D is the the midpoint of BC.
then prove that triangle ADB = triangle ADC.​

Answer 1

Answer:

∆ADB=∆ADC

Step-by-step explanation:

Given, ∆ADB=∆ADC

<ADB=<ADC [ AD is bisector of angle BAC)

AB = AC (side)

<BAD=<DAC (angle)

therefore,∆ADB=∆ADC

it satisfies ASA