Question

The 4th question pls
Whoever gives me the correct answer will be marked as brainliest

Answer 1

heyy...here is ur ans...☺✌

we know that the sum of all angles of quadrilateral is 360°

so here in this quad.

<P + <N + <O + <M = 360

<P + 90 +90 +40 = 360

<P = 360 - 220

<P = 140°

hope it helps u....if it did plzz mark me brainliest.....thanks☺✌

Answer 2

SoluTion :-

We have to find ∡ MPN

$\sf {In\ quadrilateral\ OMPN }\\\\\\\sf {\angle MON+ \angle ONP +\angle MPN + \angle PMO = 360^o}\\\\\sf {40^{o}+90^{o}+\angle MPN+90^{o}=360^{o}}\\\\\sf {220^{o}+\angle MPN=360^{o}}\\\\\\\sf {\angle MPN = 360^{o}-220^{o}}\\\\\sf {\angle MPN = 140^{o}}$