Question

in industrial preparation of Nitric acid,how many moles of NO2 are required to form 7.33 moles HNO3

Answer 1

In industrial preparation of HNO3...

3NO2 + H2O ---> 2HNO3 + NO

so as it can be inferred from the reaction,
3 moles of NO2 produce 2 moles of HNO3
x moles of NO2 produce 7.33 moles of HNO3

Therefore,
x = 7.33 x 3 / 2
x = 10.995 moles

10.995 moles of NO2 are required to produce 7.33 moles of HNO3

Answer 2

Answer:

3 NO2 + H2O --------------> 2 HNO3  + NO

 SO 2  moles of HNO3 are produced by = 3 moles of NO2

 so  7.33 mole -------------------------------------= 3 x7.33/2 of NO2

                                                        = 10 . 995 moles of NO2