in iron cylindrical pipe has thickness of 0.5 cm and external diameter of 4.5 CM if the mass of 1 cm and of the metal that is 8 gram find the mass of 77 cm long pipe
Answers
Answered by
5
volume of cylinder= [(4.5cm)²π X 77cm] - [(4cm)²π X 77cm]
= 77xπx( 4.5²-4²)cm³
= 241.9 x (4.5+4) x (4.5-4)cm³
=241.9 x 8.5 x 0.5cm³
= 1028.075
mass= 1028.075 x 8g
= 8224.6
= 77xπx( 4.5²-4²)cm³
= 241.9 x (4.5+4) x (4.5-4)cm³
=241.9 x 8.5 x 0.5cm³
= 1028.075
mass= 1028.075 x 8g
= 8224.6
Answered by
1
Answer:
hope it help you
Step-by-step explanation:
please make brainlist answer
Attachments:
Similar questions