Question

in isolus triangle right angled at C prove that a b square equal to 2 AC square

Answer 1

I hope this would be helpful to you

Answer 2

Given that ΔABC is an isosceles triangle right angled at C.

In ΔACB, ∠C = 90°

AC = BC (Given)

AB2 = AC2 + BC2 ([By using Pythagoras theorem]

        = AC2 + AC2 [Since, AC = BC]

AB2 = 2AC2