Math, asked by abhinav7789, 10 months ago


In June 2012, the average daily temperature was higher than 39degree Celcius for 28 days.
What was the percentage of the days for which the average daily temperature was below 39 degree celcius​

Answers

Answered by HappiestWriter012
13

There are 30 days in Month of June.

Given Data :

In June 2012, the average daily temperature was higher than 39degree Celcius for 28 days.

Number of days for which The Average temperature was above 39° = 28

Number of days for which The Average temperature was below 39° = 30 - 28 = 2 days.

To find :

Percentage of days for which Average temperature was below 39°

 =   \sf \frac {Number \:  of \:  days \:  which \:  had \:  less \:  than  \: 39°}{Total \:  days \:  in \:  June } \times 100</strong></p><p><strong>

 =  \frac{2}{30}  \times 100 \\  \\  =  \frac{2}{3}  \times 10 \\  \\  = 0.6667 \times </strong><strong>10</strong><strong>\% \\  \\  = 6.67\%

Therefore, The percentage of days for which Average temperature was below 39° is 6. 67%

Answered by nandinisalunkh
0

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