Question

In laboratory experiment,
10 g potassium chlorate sample on
decomposition gives following data ; The
sample contains 3.8 g of oxygen and the
actual mass of oxygen in the quantity of
potassium chlorate is 3.92 g. Calculate
absolute error and relative error.​​

Answer 1

2KClO 3 ⟶2KCl+3O 2 (Volume of O 2 liberated =2.24 Litres)

Moles of O 2 liberated = 22.4

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2.24 =0.1 mole

Moles of KCl formed = 2/3 ×0.1=0.067

Mass of KCl formed =0.067×74.5=5 gm