In measuring the sides of a rectangle the length is increased by 30% and breadth is increased by 20%. Find the percent value by which area changes?The relationship between the example and the idea should always be expressed.
Answers
Answer:
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Answer:
increases by 56%
Explanation:
Let A be area of rectangle and let A = 100 %
Let initial length and breadth be l and b respectively
Length after increased by 30% ⇒ L = l + 30% of l
⇒ L = l + (30 l / 100)
⇒ L = (100 l + 30 l) / 100
⇒ L = 130 l / 100
⇒ L = 13 l / 100
Breadth after increased by 20% ⇒ B = b + 20% of b
⇒ B = b + (20b/100)
⇒ B = (100b + 20b)/ 100
⇒ B = 120b / 100
⇒ B = 12b / 10
⇒ B = 6b/5
Area, A = L × B
⇒ A = (13l / 10) × (6b/5)
⇒ A = (39lb/25) × 100%
⇒ A = 156%
⇒ Increased area = 156% - 100% = 56 %
∴ The area is increased by 56%,
because the the area before increasing the length and breadth by 30% and 20% respectively is 100%