In n (A) = 7 ,n (B) = 13, n ( A intersection B ) = 4 , then n (A U B ) = ?
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n(a)=7
n(b)=-13
n(anb)=4
=7-13-4
7-17
-10
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Answer:
N(A) =7. N(B)=13. N((AnB)=4 n(AUB) =?
N(AUB) = n (A) + n (B)-n (AnB)
n (AUB=7+13-4
=20-4
= 16
n(AUB) =16
it's a King
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