In na and al3 which is in smallest size f o2- al3+ mg2+
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ve sign means more of electrons and +ve sign means lack of electrons.
Here N3- with atomic no. 7 has 7+3= 10 electrons
O2- witha tomic no. 8 has 8+2 = 10 electrons
F- with atomic no. 9 has 9+1= 10 electrons
Na+ with atomcatomic no. 11 has 9-1= 10 electrons
Mg2+with atomcatomic no. 12 has 12-2= 10 electrons
Al3+with atomcatomic no. 13 has 13-3= 10 electrons
Since all these ions have 10 electrons in their shell therefore these are isoelectronic speicies
The more + the charge, the smaller the ionic radius. Remember that - means adding electrons. These electrons go in the outermost shells. Also, when an atom loses electrons, it clings ever more tightly to the ones it has left, further reducing the ionic radius. therefore the order of ionic radii will be →
AL3+ Mg2+ Na+ F- O2- N3- (increasing order)
Here N3- with atomic no. 7 has 7+3= 10 electrons
O2- witha tomic no. 8 has 8+2 = 10 electrons
F- with atomic no. 9 has 9+1= 10 electrons
Na+ with atomcatomic no. 11 has 9-1= 10 electrons
Mg2+with atomcatomic no. 12 has 12-2= 10 electrons
Al3+with atomcatomic no. 13 has 13-3= 10 electrons
Since all these ions have 10 electrons in their shell therefore these are isoelectronic speicies
The more + the charge, the smaller the ionic radius. Remember that - means adding electrons. These electrons go in the outermost shells. Also, when an atom loses electrons, it clings ever more tightly to the ones it has left, further reducing the ionic radius. therefore the order of ionic radii will be →
AL3+ Mg2+ Na+ F- O2- N3- (increasing order)
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