Question

in natural numbers from 10 to 250 ,how many are divisible by 6

Answer 1

they form an A.P.
the A.P. is 12,18,24,...........246
by the formula l = a+ ( n-1)d
(where l is the last term of the A.P. , a is the first term and n is the number of terms and d is the common difference.)
246 = 12 + (n-1)x 6
246-12= (n-1)x 6
234 /6 =( n-1)
39 = n-1
39+1 = n
n = 40
Therefore 40 numbers are divisible by 6 in natural numbers from 10 to 250.
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