Chemistry, asked by shreyasoni92, 11 months ago

In one case ,1.75g of the metal were dissolved in nitrc acid and igniting the residual copper nitrate yielded 2.19 g of copper oxide.

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Answered by Anonymous
0

your question is incomplete .

A complete question is attached as shown in figure.

Solution :- 1st method :- weight of Cu : 1.75 g

weight of CuO : 2.19 g

Ratio of weight of Cu and CuO = 1.75 : 2.19 = 1 : 0.7990 ≈ 5 : 4

2nd method :- weight of Cu : 1.14g

weight of CuO : 1.43g

Ratio of weight of Cu and CuO = 1.14 : 1.43 = 1 : 0.7972 ≈ 5 :4

From method 1st and 2nd , it is clear that Cu combined with Oxygen with constant ratio. Hence, the given date is a illustration of the law of constant composition.

Answered by Mraduljaiswal2005
1

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