Question

in one day cricket match Sachin played 40 balls and hit 12 sixes and saurabh play 30 balls and hit 9 hours find the probability that Sachin will hit a six in the next ball and also find probability that saurabh will not hit four in next

Answer 1

probabilyy of sachin hitting a six = 12/40=6/20
probability of saurabh not hitting a four = 21/30=7/10

Answer 2

Probability of hitting a six
= Number if sixes/Total balls
= 12/40
= 3/10

Probability that Saurabh will not hit a four
= 1 - Probability of hitting four
= 1 - 9/30
= 21/30
= 7/10