Question

In one DNA coil 2 Adenine are present. calculate total no of
4 bonds present in that coil out of 20 molecules​

Answer 1

Answer:

B-DNA contains approximately 10 base pairs per coil, so 20 coils contain 200 base pairs. 120 adenine molecules correspond to 120 A-T base pairs. Number of G-C base pairs is 200-120=80.

Pyrimidine nucleotide forming 3 hydrogen bonds is cytidine monophosphate, so number of cytosine molecules is 80.

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