Question

In order to celebrate Van Mahostav, the students of school planned to plant two types of trees in a park. They decided to plant 144 trees of type A and 84 trees of type B. If same no. of trees of each type are to be planted in each column separately, find the minimum no. of columns in which they can be planted.


REMEMBER !! MINIMUM NO OF COLUMNS

Answer 1

Answer:12

Step-by-step explanation:Maximum number of columns in which the two types of plants can be planted = HCF of 144 and 84 Since 144>84

So, by division lemma, 144=84×1+60

Again, applying division lemma (since remainder



=0), we get

84=60×1+24

Continuing the same way,

60=24×2+12 and 24=12×2+0

∴ Remainder at this stage =0

∴ HCF (144, 84)=12

Answer 2

minimum number of columns is 1008

Step-by-step explanation:

144=12×12

84=12×7

HCF is 12

nd minimum number of columns is 12×12×7

means minimum number of columns is 1008

thank you