Question

In order to have 6P2 permutations, the 6C2 combinations of 'flight' should be multiplied by:​

Answer 1

Step-by-step explanation:

mark me as brainlist please guy

Answer 2

Answer:

In order to have $^6P_2$ permutations, the combinations $^6C_2$ should be multiplied by 2.

Step-by-step explanation:

We know that the formula for finding the permutations of any event, 'r', from a total of 'n' possibilities is as follows:

$^nP_r=\frac{n!}{(n-r)!}$                   ...(i)

Also, we know that the expression for finding the combinations of any event, 'r', from a total of 'n' possibilities is as follows:

$^nC_r=\frac{n!}{r!\times(n-r)!}$             ...(ii)

So, for finding the value for the permutations, $^nP_r$ from a given number of combinations, $^nC_r$, substituting (i) in (ii), we get:

$^nC_r=\frac{^nP_r}{r!}$

or we can say:

$^nP_r=^nC_r\times r!$

Thus, we need to multiply $r!$ with $^nC_r$ to get the result as $^nP_r$.

In the given problem for finding $^6P_2$ from $^6C_2$, the value for $r$ is 2.

Here, 2! = 2, so, we should multiply $^6C_2$ by 2 to get the result as $^6P_2$.