Question

IN ORDER TO MEASURE LOSS IN WIEGHT OF A SOLID, A STUDENT NOTED DOWN THE APPARENT WEIGHT OF THE SOLID IN LIQUID 'A' AND LIQID 'B' USING A SPRING BALANECE AS 45 GWT AND 25 GWT. RESPECTIVELY. IF THE TRUE WEIGHT OF SOLID IN AIR IS 65 GWT, I)WHICH LIQUID HAS GREATER DENSITY ? II) WHICH LIQUID EXERTS A GREATER BUOYANT FORCE ON THE SOLID

Answer 1

I) liquid B has greater density.
II) since buoyant force is directly proportional to the density, then Liquid B exerts a greater buoyant force on the solid.

Answer 2

Given:

Apparent Weight of solid in liquid A  = 45 gwt

Apparent Weight of solid in liquid B = 25 gwt

True weight of solid = 65 gwt

Formula Used:

Apparent weight = True weight - Buoyant force

Buoyant force, $F_B=\rho V g$

where, $\rho$ is the density of the fluid, V is the volume of the solid and g is the gravitational constant.

Calculation:

$F_B (A) = 65-45 = 20 gwt\\F_B(B) = 65-25 = 40 gwt$

This means that liquid B exerts greater buoyant force.

Volume of the solid and value of g remains same.

$F_B \propto \rho$

$F_B(B)>F_B(A)\\\Rightarrow \rho_B > \rho_A$

Liquid B has greater density.

Learn more about: Buoyant force

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