Question

In p (x)=3x³-3x²+5x-k p(2)=0 find k?​

Answer 1

Answer:

Given polynomials are p(x)=kx

3

+3x

2

−3 and Q(x)=2x

3

−5x+k.

It is also given that these two polynomials leave the same remainder when divided by (x−4), therefore, we equate the polynomials and substitute x=4 as shown below:

k(4)

3

+3(4)

2

−3=2(4)

3

−5(4)+k

⇒64k+48−3=128−20+k

⇒64k+45=k+108

⇒64k−k=108−45

⇒63k=63

⇒k=1

Hence, k=1.

Answer 2

Answer:

Step-by-step explanation:

Given that,

p ( x ) = 3x³ - 3x² + 5x - k

p ( 2 ) = 3 ( 2 )³ - 3 ( 2 )² + 5 ( 2 ) - k = 0

⇒ 3 ( 8 ) - 3 ( 4 ) + 10 - k = 0

⇒24 - 12 + 10 - k = 0

⇒ 34 - 12 - k = 0

⇒ 22 - k = 0

⇒ k = 22 is the answer.