In parallel series a=7,a¹³=35 is given, find d and S¹³
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1
Answer:
a=7,a
13
=35
a
13
=a+(13−1)d
35=7+12d
28=12d
d=28/12=7/3
s
13
=
2
13
[2a+(13−1)
3
7
]
s
13
=
2
13
[14+(12)
3
7
]
s
13
=
2
13
[14+28]
s
13
=13×21
s
13
=273
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