Question

in parallelogram ABCD 3angleA=2angleB,then find angle D.​

Answer 1

Answer:

the answer is 3angleA divided by 2

Answer 2

Step-by-step explanation:

Let angleA and angleB be p and q.

then p + q = 180 ........(i)

also 3p = 2q

q = 3p/2 .......(ii)

Putting (ii) in (i), we get

p + 3p/2 = 180

5p = 360

p = 72°

Hence angle D = p = 72°