In parallelogram ABCD, AB>AD. Prove that
angleADB>angleBDC
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Step-by-step explanation:
ANSWER
Opposite angles of parallelogram are equal.
∠DAB=∠BCD=75
o
and ∠DBC=60
o
∠BDC+∠DBC+∠BCD=180
o
∠BDC=180
o
−∠DBC−∠BCD=180
o
−75
o
−60
o
=45
o
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