Question

In parallelogram ABCD angle A=angle b+50 then find the measure of each angle of the quadrilateral ABCD

Answer 1

Answer:

A= 115,B= 65, D=115 ,C= 65

Step-by-step explanation:

Gvn,in llgm ABCD

A= b+50

then B= b

As sum of the opposite angles is 180

A + B = 180

b+50 + b= 180

2b+50= 180

2b= 180 - 50

2b= 130

b= 130/2

b=65

Hence,A=b+50=115

B=b=65(ans)

!!!!!!!!!HOPE THIS WILL HELP YOU!!!!!!!!

Answer 2

Answer:

$\angle \: A = \angle \: C = 115° \\ \angle \: B = \angle \: D= 65°$

Step-by-step explanation:

We know that in a parallelogram Sum of adjacent angles are 180°.

$\angle \: A + \angle \: B = 180°\\ \\ ...eq1$

given that

$\angle \: A = \angle \: B + 50° \\ \\\angle \: A - \angle \: B = 50°...eq2$

from equation 1 and 2

$2\angle \: A = 230° \\ \\ \angle \: A = 115°$

$\angle \:C = 115°$

[because opposite angles are equal]

From eq1

$\angle \: B = \angle \: D = 65 °$

Hope it helps you.